JEE Advanced 2017Paper 2
- Exam
- JEE Advanced
- Year
- 2017
- Paper
- Paper 2
- Subject
- Mathematics
- Chapter
- Trigonometric Equations
JEE Advanced 2017 · Paper 2 · Mathematics · Trigonometric Equations
Let α and β be non zero real numbers such that 2(cos β - cos α) +...
Let and be non zero real numbers such that . Then which of the following is/are true?
Options
- A\tan \left(\dfrac{α}{2}\right) - \sqrt{3}\tan \left(\dfrac{β}{2}\right) = 0
- B
- C\tan \left(\dfrac{α}{2}\right) + \sqrt{3}\tan \left(\dfrac{β}{2}\right) = 0
- D
Correct answer
A. \tan \left(\dfrac{α}{2}\right) - \sqrt{3}\tan \left(\dfrac{β}{2}\right) = 0
Step-by-step solution
2\left(cos β - cos α\right) + cos αcos β - 1 = 0 .....(i)
Use cos β = \dfrac{1 - \tan^{2} \dfrac{β}{2}}{1 + \tan^{2} \dfrac{β}{2}}andcos α = \dfrac{1 - \tan^{2} \dfrac{α}{2}}{1 + \tan^{2} \dfrac{α}{2}} in (i)
We get \tan^{2} \left(\dfrac{α}{2}\right) = 3\tan^{2} \left(\dfrac{β}{2}\right) \to \tan \left(\dfrac{α}{2}\right) + \sqrt{3}tan \dfrac{β}{2} = 0ortan \left(\dfrac{α}{2}\right) - \sqrt{3}\tan \left(\dfrac{β}{2}\right) = 0