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JEE Advanced2010MathematicsTrigonometric EquationsActual

The number of values of in the interval (- 2 , 2 ) such that n 5 for n=0, 1, 2 and = 5 as well as 2 = 4 is

Correct answer

3

Step-by-step solution

Given, = 5 aligned & = ( 2 -5 ) & 2 -5 =n + & 6 = 2 -n & = 12 - n 6 & Also, 4 = 2 = ( 2 -2 ) & 4 =2 n ( 2 -2 ) aligned Taking positive 6 =2 n + 2 = n 3 + 12 Taking negative 2 =2 n - 2 =n - 4 Above values of suggests that there are only 3 common solutions.

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