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JEE Advanced 2017Paper 1
Exam
JEE Advanced
Year
2017
Paper
Paper 1
Subject
Physics
Chapter
Center of Mass, Momentum and Collision

JEE Advanced 2017 · Paper 1 · Physics · Center of Mass, Momentum and Collision

A flat plate is moving normal to its plane through a gas under the...

A flat plate is moving normal to its plane through a gas under the action of a constant force F. The gas is kept at a very low pressure. The speed of the plate v I much less than the average speed u of the gas molecules. Which of the following options is true?A flat plate is moving normal to its plane through a gas under the action of a constant force F. The gas is kept at aA flat plate is moving normal to its plane through a gas under the action of a constant force F. The gas is kept at a

Options

  1. AAt a later time the external force F balances the resistive force
  2. BThe resistive force experienced by the plate is proportional to v
  3. CThe plate will continue to move with constant non zero acceleration at all times
  4. DThe pressure difference between the leading and trailing faces of the plate is proportional to uvuv

Correct answer

A. At a later time the external force F balances the resistive force

Step-by-step solution

A flat plate is moving normal to its plane through a gas under the action of a constant force F. The gas is kept at a

v1=u+2v{v}_{1} = u + 2v

v2=(u−2v){v}_{2} = \left(u - 2v\right)

Δv1=(2u+2v)\Delta{v}_{1} = \left(2u + 2v\right)

Δv2=(2u−2v)\Delta{v}_{2} = \left(2u - 2v\right)

F1=dp1dt=ρA(u+v)(2u+2v){F}_{1} = \dfrac{d{p}_{1}}{dt} = ρA\left(u + v\right)\left(2u + 2v\right)

F2=dp2dt=ρA(u−v)(2u−2v){F}_{2} = \dfrac{d{p}_{2}}{dt} = ρA\left(u - v\right)\left(2u - 2v\right)

=2ρA(u+v)2= 2ρA{\left(u + v\right)}^{2}

=2ρA(u−v)2= 2ρA{\left(u - v\right)}^{2}

A flat plate is moving normal to its plane through a gas under the action of a constant force F. The gas is kept at a

\DeltaF=F1−F2\DeltaF = {F}_{1} - {F}_{2} (\DeltaF\DeltaFnet force due to the air molecules on the plate)

=2ρA(4uv)=8ρAuv= 2ρA\left(4uv\right) = 8ρAuv

P=\DeltaFA=8ρ(uv)P = \dfrac{\DeltaF}{A} = 8ρ\left(uv\right)

Fnet=(F−\DeltaF)=ma{F}_{net} = \left(F - \DeltaF\right) = ma (m is mass of the plate)

F−(8ρAu)v=maF - \left(8ρAu\right)v = ma

 

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