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JEE Advanced 2016Paper 2
Exam
JEE Advanced
Year
2016
Paper
Paper 2
Subject
Physics
Chapter
Current Electricity

JEE Advanced 2016 · Paper 2 · Physics · Current Electricity

Paragraph: Consider an evacuated cylindrical chamber of height h...

Paragraph: Consider an evacuated cylindrical chamber of height hh having rigid conducting plates at the ends and an insulating curved surface as shown in the figure. A number of spherical balls made of a light weight and soft material and coated with a conducting material are placed on the bottom plate. The balls have a radius r≪hr \ll h. Now a high voltage source (HV)(HV) is connected across the conducting plates such that the bottom plate is at +V0+V_{0} and the top plate at −V0.-V_{0} . Due to their conducting surface, the balls will get charged, will become equipotential with the plate and are repelled by it. The balls will eventually collide with the top plate, where the coefficient of restitution can be taken to be zero due to the soft nature of the material of the balls. The electric field in the chamber can be considered to be that of a parallel plate capacitor. Assume that there are no collisions between the balls and the interaction between them is negligible. (Ignore gravity) Paragraph: Consider an evacuated cylindrical chamber of height h having rigid conducting plates at the ends and an

Question: The average current in the steady state registered by the ammeter in the circuit will be

Options

  1. AProportional to V012{V}_{0}^{\dfrac{1}{2}}
  2. BProportional to V02{V}_{0}^{2}
  3. CProportional to the potential V0{V}_{0}
  4. DZero

Correct answer

B. Proportional to V02{V}_{0}^{2}

Step-by-step solution

Paragraph: Consider an evacuated cylindrical chamber of height h having rigid conducting plates at the ends and an
h=12at2h = \dfrac{1}{2}a{t}^{2} [as u = 0]
2hmqE=time⇒time=2mq∆V\sqrt{\dfrac{2hm}{qE}} = time ⇒ time = \sqrt{\dfrac{2m}{q ∆ V}}
E=V0hE = \dfrac{{V}_{0}}{h}
=chargetime=qqV02mh2= \dfrac{charge}{time} = \dfrac{q\sqrt{q{V}_{0}}}{2m{h}^{2}}
q∞V0q\infty{V}_{0}
∞V02\infty{V}_{0}^{2}
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