A conducting loop in the shape of right angled isosceles triangle...

From lenz's law it can be understood that due to induced current in wire flux will change in loop thats why it will be repelled by the loop

Also by direction of induced electric field, the current in the wire is in the same direction of current along the hypotenuse.
Flux through triangle if wire has current ${i}_{1}$ 

${ϕ}_{2} = {∫}_{0}^{0 . 1}B d A$

$= \mathop{∫}_{0}^{0.1}\left(\dfrac{{\mu}_{0}{i}_{1}}{2\pix}\right)\left(2xdx\right) = \dfrac{{\mu}_{0}{i}_{1}}{10\pi}$

$⇒ {ϕ}_{2} = M{i}_{1}$
$⇒$ Mutual inductance $M = \dfrac{{\mu}_{0}}{10\pi}$
Induced emf in wire

${ε}_{1} = M\dfrac{d{i}_{2}}{dt}$

$= \dfrac{{\mu}_{0}}{10\pi}\dfrac{d{i}_{2}}{dt} = \dfrac{{\mu}_{0}}{10\pi} \times 10 = \dfrac{{\mu}_{0}}{\pi}$