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JEE Advanced 2020Paper 2
Exam
JEE Advanced
Year
2020
Paper
Paper 2
Subject
Physics
Chapter
Electromagnetic Waves

JEE Advanced 2020 · Paper 2 · Physics · Electromagnetic Waves

In an X -ray tube, electrons emitted from a filament (cathode)...

In an XX-ray tube, electrons emitted from a filament (cathode) carrying current II hit a target (anode) at a distance dd from the cathode. The target is kept at a potential VV higher than the cathode resulting in emission of continuous and characteristic X-rays. If the filament current II is decreased to I2,\dfrac{I}{2}, the potential difference VV is increased to 2V,2V, and the separation distance dd is reduced to d2,\dfrac{d}{2}, then

Options

  1. Athe cut-off wavelength will reduce to half, and the wavelengths of the characteristic X-rays will remain the same
  2. Bthe cut-off wavelength as well as the wavelengths of the characteristic X-rays will remain the same
  3. Cthe cut-off wavelength will reduce to half, and the intensities of all the X-rays will decrease
  4. Dthe cut-off wavelength will become two times larger, and the intensity of all the X-rays will decrease

Correct answer

A. the cut-off wavelength will reduce to half, and the wavelengths of the characteristic X-rays will remain the same

Step-by-step solution

Cut off wavelength λC∝1V{\lambda}_{C} ∝ \dfrac{1}{V}

So, cut-off wavelength becomes half.

Characteristic x-ray depends on target atomic number, so it remains same.

On decreasing filament current number of electron decrease, so intensity of XX -ray decreases.

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