For a plane electromagnetic wave, the magnetic field at a point $x$ and time $t$ is :
$\overset{\to}{B}\left(x, t\right) = \left[1 .2 \times {10}^{- 7}\sin \left(0 .5 \times {10}^{3}x + 1 .5 \times {10}^{11}t\right)\overset{^}{k}\right]T$ .
The instantaneous electric field $\overset{\to}{E}$ corresponding to $\overset{\to}{B}$ is :

Question

For a plane electromagnetic wave, the magnetic field at a point $x$ and time $t$ is :

$\overset{\to}{B}\left(x, t\right) = \left[1 .2 \times {10}^{- 7}\sin \left(0 .5 \times {10}^{3}x + 1 .5 \times {10}^{11}t\right)\overset{^}{k}\right]T$ .

The instantaneous electric field $\overset{\to}{E}$ corresponding to $\overset{\to}{B}$ is :

Quantrex Academy · Accepted Answer

Correct answer: A. → E (x, t) = [- 36 (0 . 5 × 10 ^ 3 x + 1 . 5 × 10 ^ 11 t) ^ j ](V)/(m)

E _ 0 = B _ 0 × C = 1 . 2 × 10 ^ - 7 × 3 × 10 ^ 8 = 36 As the light is propagating in x direction. & ( ^ E × ^ B ) | | ^ C ∴ → E should be in ^ j direction. So electric field → E = E _ 0 sin → E · ( x, t ) = [- 36 (0 . 5 × 10 ^ 3 x + 1 . 5 × 10 ^ 11 t) ^ j ](V)/(m)

For a plane electromagnetic wave, the magnetic field at a point x...

Options

Correct answer

Step-by-step solution

More from Electromagnetic Waves