Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
JEE Advanced 2020Paper 2
Exam
JEE Advanced
Year
2020
Paper
Paper 2
Subject
Physics
Chapter
Electrostatics

JEE Advanced 2020 · Paper 2 · Physics · Electrostatics

Two large circular discs separated by a distance of 0 . 01m are...

Two large circular discs separated by a distance of 0.01m0 . 01m are connected to a battery via a switch as shown in the figure. Charged oil drops of density 900kgm−3900kg{m}^{- 3} are released through a tiny hole at the centre of the top disc. Once some oil drops achieve terminal velocity, the switch is closed to apply a voltage of 200V200V across the discs. As a result, an oil drop of radius 8×10−7m8 \times {10}^{- 7}m stops moving vertically and floats between the discs. The number of electrons present in this oil drop is __________. (neglect the buoyancy force, take acceleration due to gravity =10ms−2= 10m{s}^{- 2} and charge on an electron (e) =1.6×10−19C= 1 . 6 \times {10}^{- 19}C)

Two large circular discs separated by a distance of 0 . 01m are connected to a battery via a switch as shown in the

Correct answer

0

Step-by-step solution

qE=mgqE = mg

q=mgE=900×43π(8×10−7)3×10(2000.01)q = \dfrac{mg}{E} = \dfrac{900 \times \dfrac{4}{3}\pi{\left(8 \times {10}^{- 7}\right)}^{3} \times 10}{\left(\dfrac{200}{0 . 01}\right)}

=900×43π×512×10−21×102×104= \dfrac{900 \times \dfrac{4}{3}\pi \times 512 \times {10}^{- 21} \times 10}{2 \times {10}^{4}}

N=900×43π×512×10−21×102×104×1.6×10−19N = \dfrac{900 \times \dfrac{4}{3}\pi \times 512 \times {10}^{- 21} \times 10}{2 \times {10}^{4} \times 1 . 6 \times {10}^{- 19}}

N≈6N \approx 6

Practice Electrostatics on Quantrex Academy →

More from Electrostatics

Two charges Q_1 = q and Q_2 = mq are placed at the points P_1(a, b) and P_2(ma, mb)… JEE Advanced 2026Consider an electric dipole comprising two charges +q and -q each with mass m , separated… JEE Advanced 2026Two point charges q_1=3\,μ C and q_2=-4\,μ C are placed at points (2 i +3 j +3 k ) and (… JEE Main 2026The electric potential as a function of x, y is given by V = 5(x^2 - y^2) V. The electric… JEE Main 2026A thin half ring of radius 35 cm is uniformly charged with a total charge of Q coulomb.… JEE Main 2026A three coulomb charge moves from the point (0, -2, -5) to the point (5, 1, 2) in an… JEE Main 2026A particle of charge q and mass m is projected from origin with an initial velocity v = (… JEE Main 2026A rigid dipole undergoes a simple harmonic motion about its centre in the presence of an… JEE Main 2026 Full Electrostatics list All JEE Advanced PYQs