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JEE Advanced2010PhysicsGravitationActual

Gravitational acceleration on the surface of a planet is 6 11 ~g , where g is the gravitational acceleration on the surface of the earth. The average mass density of the planet is 2 3 times that of the earth. If the escape speed on the surface of the earth is taken to be 11 kms ⁻¹ , the escape speed on the surface of the planet in kms ⁻¹ will be

Correct answer

3

Step-by-step solution

g= G M R^2 = G ( 4 3 R^3 ) R^2 or g R or R g Now escape velocity, v_e= 2 g R or v_e g R or v_e g g g^2 (v_e )_ planet = (11 ~km - s ⁻¹ ) 6 121 3 2 The correct answer is 3 .

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