A spherically symmetric gravitational system of particles has a mass density =\ array l _0 for r ≤ R 0 for r>R array . where _0 is a constant. A test mass can undergo circular motion under the influence of the

Correct answer: C. For r ≤ R : (m v^2)/(r)= G · m m^ r^2 Here, m^ =((4)/(3) π r^3) _0 Substituting in Eq. (i) we get, v r i.e., v-r graph is a straight line passing through origin. For r R : (m v^2)/(r)=(G · m((4)/(3) π R^3) _0)/(r^2) or V 1 r The corresponding v-r graph will be as shown in option (c). correct option is (c).

JEE Advanced 2008Paper 1

Exam: JEE Advanced
Year: 2008
Paper: Paper 1
Subject: Physics
Chapter: Gravitation

JEE Advanced 2008 · Paper 1 · Physics · Gravitation

A spherically symmetric gravitational system of particles has a...

A spherically symmetric gravitational system of particles has a mass density

\rho=\left\{

\begin{array}{l} \rho_0 \text{ for } r \leq R \\ 0 \text{ for } r>R \end{array}

\right.

where

\rho_0

is a constant. A test mass can undergo circular motion under the influence of the gravitational field of particles. Its speed

v

as a function of distance

r(0 < r < \infty)

from the centre of the system is represented by $A spherically symmetric gravitational system of particles has a mass density =\ array l _0 for r ≤ R 0 for r>R array .$ $A spherically symmetric gravitational system of particles has a mass density =\ array l _0 for r ≤ R 0 for r>R array .$ $A spherically symmetric gravitational system of particles has a mass density =\ array l _0 for r ≤ R 0 for r>R array .$ $A spherically symmetric gravitational system of particles has a mass density =\ array l _0 for r ≤ R 0 for r>R array .$