An incompressible liquid is kept in a container having a weightless piston with a hole. A capillary tube of inner radius 0 . 1 mm is dipped vertically into the liquid through the airtight piston hole, as shown in the figure. The air in the container is isothermally compressed from its original volume V 0 to 100 101 V 0 with the movable piston. Considering air as an ideal gas, the height h of the liquid column in the

Step-by-step solution

Let P f be the air pressure. As the process is isothermal, we can write P 0 V 0 = P f V f ⇒ P 0 V 0 = P f 100 101 V 0 ⇒ P f = 101 × 10 3   Pa                     ∵   P 0 = 10 5   N   m - 2 Now, consider the 4 points shown in diagram P d - P c = 2 T R                     ∵   P d = P 0 ∴   P c = P 0 - 2 T R Now, P a = P b (also, P a = P f ) ⇒ P f =