A cylindrical furnace has height H and diameter D both 1 m . It is maintained at temperature 360 K . The air gets heated inside the furnace at constant pressure P a and its temperature becomes T = 360 K . The hot air with density ρ rises up a vertical chimney of diameter d = 0 . 1 m and height h = 9 m above the furnace and exits the chimney (see the figure). As a result, atmospheric air of density ρ a = 1 .

Step-by-step solution

Applying Bernoulli’s theorem between top and bottom points of furnace : P a + 1 2 ρ a V 2 = P a + ρ g H + 1 2 ρ V 2                                 . . .   1 Also, since P M = ρ R T ⇒   ρ a × 300 = ρ × 360 ⇒   ρ = 1   kg   m - 3                           . . .   2 From equation(1),