A cubical solid aluminum (bulkmodulus = - V(dP)/(dV) = 70GPa) block...

$B = \dfrac{P}{\left(- \dfrac{dV}{V}\right)} ⇒ \dfrac{dV}{V} = - \dfrac{P}{B} ⇒ 3\dfrac{dℓ}{ℓ} = \dfrac{P}{B}$

$dℓ = \left(\dfrac{- P}{B}\right)\dfrac{ℓ}{3} = \dfrac{{10}^{3}\dfrac{kg}{{m}^{3}} \times \dfrac{10m}{{s}^{2}} \times 5 \times {10}^{3}}{70 \times {10}^{9}} \times \dfrac{1m}{3}$

$dℓ = 0 . 238 \times {10}^{- 3}$

$⇒ dℓ = 0 . 238mm$

$= 0 . 24$