A cube of metal is subjected to a hydrostatic pressure 4 G P a . The percentage change in the length of the side of the cube is close to : (Given bulk modulus of metal, B = 8 × 10 10 P a )

Step-by-step solution

B = - ∆ P ∆ V V ∆ V V = - ∆ P B Magnitude is given by, ∆ V V = ∆ P B Volume in terms of length can be represented as, 3 × ∆ L L = ∆ P B Therefore, ∆ L L = 1 3 × ∆ P B Substituting the values we get, ∆ L L = 1 3 × 4 × 10 9 8 × 10 10 = 1 60 Percantage change is, 1 60 × 100 = 5 3 = 1 . 67