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JEE Advanced 2011Paper 2
Exam
JEE Advanced
Year
2011
Paper
Paper 2
Subject
Physics
Chapter
Oscillations

JEE Advanced 2011 · Paper 2 · Physics · Oscillations

A wooden block performs SHM on a frictionless surface with...

A wooden block performs SHM on a frictionless surface with frequency v0v_0. The block carries a charge +Q+Q on its surface. If now a uniform electric field E\mathbf{E} is switched on as shown, then the SHM of the block will be A wooden block performs SHM on a frictionless surface with frequency v_0 . The block carries a charge +Q on its

Options

  1. Aof the dame frequency and with shifted mean position
  2. Bof the same frequency and with the same mean position
  3. Cof changed frequency and with shifted mean position
  4. Dof changed frequency and with the same mean position

Correct answer

A. of the dame frequency and with shifted mean position

Step-by-step solution

Frequency or time period of SHM depends on variable forces. It does not depend on constant external force. Constant external force can only change the mean position. For example, in the given question mean position is at natural length of spring in the absence of electric field. Whereas in the presence of electric field mean position will be obtained after a compression of x0x_0. Where x0x_0 is given by or kx0=QEx0=QEk\begin{aligned}k x_0 & =Q E \\ x_0 & =\frac{Q E}{k} \end{aligned}\therefore$ Correct answer is (a). Analysis of Question (i) Question is simple. (ii) I think almost all the serious aspirants of JEE can solve this problem easily.
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