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JEE Advanced 2010Paper 1
Exam
JEE Advanced
Year
2010
Paper
Paper 1
Subject
Physics
Chapter
Oscillations

JEE Advanced 2010 · Paper 1 · Physics · Oscillations

When two progressive waves y_1=4 (2 x-6 t) and y_2=3 (2 x-6...

When two progressive waves y1=4sin⁡(2x−6t)y_1=4 \sin (2 x-6 t) \quad and y2=3sin⁡(2x−6t−π2)y_2=3 \sin \left(2 x-6 t-\frac{\pi}{2}\right) \quad are superimposed, the amplitude of the resultant wave is

Correct answer

5

Step-by-step solution

Phase difference between the two waves is 90∘90^{\circ}. Amplitudes are added by vector method. ∴\therefore Answer is 5 .
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