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JEE Advanced2008PhysicsOscillationsActual

Paragraph: A uniform thin cylindrical disk of mass M and radius R is attached to two identical massless springs of spring constant k which are fixed to the wall as shown in the figure. The springs are attached to the axle of the disk symmetrically on either side at a distance d from its centre. The axle is massless and both the springs and the axle are in a horizontal plane. The unstretched length of each spring is L

Options

  1. A-k x
  2. B-2 k x
  3. C- 2 k x 3
  4. D- 4 k x 3

Correct answer

D. - 4 k x 3

Step-by-step solution

2 k x-f M =R [ f R 1 2 M R^2 ] Solving this equation, we get f= 2 k x 3 |F_ net |=2 k x-f=2 k x- 2 k x 3 = 4 k x 3 This is opposite to displacement. F_ net =- 4 k x 3 correct option is (d).

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