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JEE Advanced 2025Paper 2
Exam
JEE Advanced
Year
2025
Paper
Paper 2
Subject
Physics
Chapter
Ray Optics

JEE Advanced 2025 · Paper 2 · Physics · Ray Optics

Two identical concave mirrors each of focal length f are facing...

Two identical concave mirrors each of focal length ff are facing each other as shown in the schematic diagram. The focal length ff is much larger than the size of the mirrors. A glass slab of thickness tt and refractive index n0n_0 is kept equidistant from the mirrors and perpendicular to their common principal axis. A monochromatic point light source SS is embedded at the center of the slab on the principal axis, as shown in the schematic diagram. For the image to be formed on SS itself, which of the following distances between the two mirrors is/are correct: Two identical concave mirrors each of focal length f are facing each other as shown in the schematic diagram. The focal

Options

  1. A4f+(1−1n0)t4 f+\left(1-\frac{1}{n_0}\right) t
  2. B2f+(1−1n0)t2 f+\left(1-\frac{1}{n_0}\right) t
  3. C4f+(n0−1)t4 f+\left(n_0-1\right) t
  4. D2f+(n0−1)t2 f+\left(n_0-1\right) t

Correct answer

A. 4f+(1−1n0)t4 f+\left(1-\frac{1}{n_0}\right) t

Step-by-step solution

Two identical concave mirrors each of focal length f are facing each other as shown in the schematic diagram. The focal
S−t2+t2n0=2fS+t(1n0−1)=4fS=4f+(1−1n0)t\begin{aligned} & \frac{S-t}{2}+\frac{t}{2 n_0}=2 f \\ & S+t\left(\frac{1}{n_0}-1\right)=4 f \\ & S=4 f+\left(1-\frac{1}{n_0}\right) t\end{aligned} Also S−t2+t2n0=fS=2f+(1−1n0)t\begin{aligned} & \frac{\mathrm{S}-\mathrm{t}}{2}+\frac{\mathrm{t}}{2 \mathrm{n}_0}=\mathrm{f} \\ & \mathrm{S}=2 \mathrm{f}+\left(1-\frac{1}{\mathrm{n}_0}\right) \mathrm{t}\end{aligned}
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