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JEE Main 20258 AprilEvening Shift
Exam
JEE Main
Year
2025
Date
8 April
Shift
Evening Shift
Subject
Physics
Chapter
Ray Optics

JEE Main 2025 · 8 April · Evening Shift · Physics · Ray Optics

A concave-convex lens of refractive index 1.5 and the radii of...

A concave-convex lens of refractive index 1.5 and the radii of curvature of its surfaces are 30 cm and 20 cm , respectively. The concave surface is upwards and is filled with a liquid of refractive index 1.3. The focal length of the liquid-glass combination will beA concave-convex lens of refractive index 1.5 and the radii of curvature of its surfaces are 30 cm and 20 cm ,

Options

  1. A50011 cm\frac{500}{11} \mathrm{~cm}
  2. B80011 cm\frac{800}{11} \mathrm{~cm}
  3. C70011 cm\frac{700}{11} \mathrm{~cm}
  4. D60011 cm\frac{600}{11} \mathrm{~cm}

Correct answer

D. 60011 cm\frac{600}{11} \mathrm{~cm}

Step-by-step solution

A concave-convex lens of refractive index 1.5 and the radii of curvature of its surfaces are 30 cm and 20 cm ,
1f=(1.3−11)(1∞−1−30)=(1.5−11)(1−30−1−30)=0.330+0.560=1100+1120=6+5600=11600f=60011 cm\begin{aligned} \frac{1}{\mathrm{f}} & =\left(\frac{1.3-1}{1}\right)\left(\frac{1}{\infty}-\frac{1}{-30}\right) \\ & =\left(\frac{1.5-1}{1}\right)\left(\frac{1}{-30}-\frac{1}{-30}\right) \\ & =\frac{0.3}{30}+\frac{0.5}{60}=\frac{1}{100}+\frac{1}{120} \\ & =\frac{6+5}{600}=\frac{11}{600} \\ \mathrm{f} & =\frac{600}{11} \mathrm{~cm}\end{aligned}
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