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JEE Advanced 2024Paper 2
Exam
JEE Advanced
Year
2024
Paper
Paper 2
Subject
Physics
Chapter
Ray Optics

JEE Advanced 2024 · Paper 2 · Physics · Ray Optics

Two equilateral-triangular prisms P_1 and P_2 are kept with their...

Two equilateral-triangular prisms P1\mathrm{P}_1 and P2\mathrm{P}_2 are kept with their sides parallel to each other, in vacuum, as shown in the figure. A light ray enters prism P1P_1 at an angle of incidence θ\theta such that the outgoing ray undergoes minimum deviation in prism P2P_2. If the respective refractive indices of P1\mathrm{P}_1 and P2\mathrm{P}_2 are 32\sqrt{\frac{3}{2}} and 3\sqrt{3}, then θ=sin⁡−1[32sin⁡(πβ)]\theta=\sin ^{-1}\left[\sqrt{\frac{3}{2}} \sin \left(\frac{\pi}{\beta}\right)\right], where the value of β\beta is _______ . Two equilateral-triangular prisms P_1 and P_2 are kept with their sides parallel to each other, in vacuum, as shown in

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Step-by-step solution

Two equilateral-triangular prisms P_1 and P_2 are kept with their sides parallel to each other, in vacuum, as shown in At surface BC 32sin⁡r2=3sin⁡3032sin⁡r2=32sinr⁡2=12r2=45∘r1=60∘−45∘=15∘\begin{aligned} & \sqrt{\frac{3}{2}} \sin \mathrm{r}_2=\sqrt{3} \sin 30 \\ & \sqrt{\frac{3}{2}} \sin \mathrm{r}_2=\frac{\sqrt{3}}{2} \\ & \operatorname{sinr}_2=\frac{1}{\sqrt{2}} \\ & \mathrm{r}_2=45^{\circ} \\ & \mathrm{r}_1=60^{\circ}-45^{\circ}=15^{\circ}\end{aligned} At surface ABA B 1sin⁡θ=32sin⁡15∘θ=sin⁡−1[32sin⁡π12]β=12\begin{array}{ll} 1 \sin \theta=\sqrt{\frac{3}{2}} \sin 15^{\circ} \\ \theta=\sin ^{-1}\left[\sqrt{\frac{3}{2}} \sin \frac{\pi}{12}\right] \\ \beta=12\end{array}
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