A glass beaker has a solid, plano-convex base of refractive index 1.60, as shown in the figure. The radius of curvature of the convex surface (SPU) is 9 ~cm , while the planar surface (STU) acts as a mirror. This beaker

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Correct answer: A. For n=1.42, h=50 ~cm .

Since STU is a plane mirror, we can take mirror image of the whole situation about it and final image can be assumed to be at a distance h below the base. Since object and image are at same distance from equivalent lens, hence h=2 ~F_ eq aligned & 1 ~F_ eq =((1.6-1)/(1))((2)/(9))+ (n-1) 1 ((-2)/(9)) & 1 h 2 =(1.2)/(9)+ 2(1-n) 9 & 2 ~h = 3.2-2 n 9 & ~h= 9 1.6-n cm aligned (1) for n=1.42, ~h=50 ~cm (2) for n=1.35, ~h=36 ~cm (3) for n=1.45, ~h=60 ~cm (4) for n=1.48, ~h=75 ~cm

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