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Three plane mirrors form an equilateral triangle with each side of length L . There is a small hole at a distance l > 0 from one of the corners as shown in the figure. A ray of light is passed through the hole at an angle θ and can only come out through the same hole. The cross section of the mirror configuration and the ray of light lie on the same plane. Which of the following statement(s) is(are) correct?

Options

  1. AThe ray of light will come out for θ = 30 ° , for 0 < l < L .
  2. BThere is an angle for l = L 2 at which the ray of light will come out after two reflections.
  3. CThe ray of light will NEVER come out for θ = 60 ° , and l = L 3 .
  4. DThe ray of light will come out for θ = 60 ° , and 0 < l < L 2 after six reflections.

Correct answer

A. The ray of light will come out for θ = 30 ° , for 0 < l < L .

Step-by-step solution

As we can see, for θ = 30 ° , the ray will incident normally and hence will retrace its path, hence the ray will come out for θ = 30 ° and 0 < l < L . ⇒ A is correct Considering the symmetry of the situation, we can have: Thus, for θ = 60 ° and l = L 2 , ray will come out from the setup after two reflections. ⇒ B is correct Now, when θ = 60 ° and l = L 3 , the ray on entering the setup will suffer five reflections and eventually will come out. As is clear

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