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JEE Advanced 2015Paper 1
Exam
JEE Advanced
Year
2015
Paper
Paper 1
Subject
Physics
Chapter
Ray Optics

JEE Advanced 2015 · Paper 1 · Physics · Ray Optics

Two identical glass rods S _ 1 and S _ 2 (refractive index = 1.5)...

Two identical glass rods S1{S}_{1} and S2{S}_{2} (refractive index = 1.5) have one convex end of radius of curvature 10 cm. They are placed with the curved surfaces at a distance d as shown in the figure, with their axes (shown by the dashed line) aligned. When a point source of light PP is placed inside rod S1{S}_{1} on its axis at a distance of 50 cm from the curved face, the light rays emanating from it are found to be parallel to the axis inside S2{S}_{2} . The distance dd is

Two identical glass rods S _ 1 and S _ 2 (refractive index = 1.5) have one convex end of radius of curvature 10 cm.

Options

  1. A60 cm
  2. B70 cm
  3. C80 cm
  4. D90 cm

Correct answer

B. 70 cm

Step-by-step solution


Two identical glass rods S _ 1 and S _ 2 (refractive index = 1.5) have one convex end of radius of curvature 10 cm.
For first surface
1v−1.5−50=1−1.5−10\dfrac{1}{v} - \dfrac{1.5}{- 50} = \dfrac{1 - 1.5}{- 10}
v=50cmv = 50cm
For second surface
1.5∞−1−(d−50)=1.5−110\dfrac{1.5}{\infty} - \dfrac{1}{- \left(d - 50\right)} = \dfrac{1.5 - 1}{10}
d=70cmd = 70cm
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