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JEE Advanced 2014Paper 2
Exam
JEE Advanced
Year
2014
Paper
Paper 2
Subject
Physics
Chapter
Ray Optics

JEE Advanced 2014 · Paper 2 · Physics · Ray Optics

A point source S is placed at the bottom of a transparent block of...

A point source S is placed at the bottom of a transparent block of height 10 mm and refractive index 2.72. It is immersed in a lower refractive index liquid as shown in the figure. It is found that the light emerging from the block to the liquid forms a circular bright spot of diameter 11.54 mm on the top of the block. The refractive index of the liquid is
A point source S is placed at the bottom of a transparent block of height 10 mm and refractive index 2.72. It is

Options

  1. A1.21
  2. B1.30
  3. C1.36
  4. D1.42

Correct answer

C. 1.36

Step-by-step solution

tanθC=rh=5.7710≈3tan {\theta}_{C} = \dfrac{r}{h} = \dfrac{5.77}{10} \approx \sqrt{3}
A point source S is placed at the bottom of a transparent block of height 10 mm and refractive index 2.72. It is
⇒θC=30o⇒ {\theta}_{C} = {30}^{o}
⇒sinθC=μlμb⇒ sin {\theta}_{C} = \dfrac{{\mu}_{l}}{{\mu}_{b}}
⇒μl=2.72×12=1.36⇒ {\mu}_{l} = 2.72 \times \dfrac{1}{2} = 1.36
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