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JEE Advanced 2006
Exam
JEE Advanced
Year
2006
Subject
Physics
Chapter
Waves and Sound

JEE Advanced 2006 · Physics · Waves and Sound

Paragraph: Two plane harmonic sound waves are expressed by the...

Paragraph: Two plane harmonic sound waves are expressed by the equations. y1(x,t)=Acos⁡(0.5πx−100πt)y2(x,t)=Acos⁡(0.46πx−92πt)\begin{aligned} & y_1(x, t)=A \cos(0.5 \pi x-100 \pi t) \\ & y_2(x, t)=A \cos(0.46 \pi x-92 \pi t) \end{aligned} (All parameters areinMKS)<strong>Question:</strong>Atx=0in MKS)<strong>Question:</strong> Atx=0 how many times the amplitude of y1+y2y_1+y_2 is zero in one second at x=0x=0 ?

Options

  1. A192
  2. B48
  3. C100
  4. D96

Correct answer

D. 96

Step-by-step solution

At x=0,y=y1+y2=2Acos⁡96πtcos⁡4πtx=0, y=y_1+y_2=2 A \cos 96 \pi t \cos 4 \pi t Frequency of cos⁡(96πt)\cos (96 \pi t) function is 48 Hz48 \mathrm{~Hz} and that of cos⁡(4πt)\cos (4 \pi t) function is 2 Hz2 \mathrm{~Hz}. In one second cos function becomes zero at 2f2 f times, where ff is the frequency. Therefore, first function will become zero at 96 times and the second at 4 times. But second overlaps with first. Hence, net yy will become zero 96 times in 1 second.
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