JEE Main2006PhysicsWaves and SoundActual
A whistle producing sound waves of frequencies 9500 ~Hz and above is approaching a stationary person with speed v ~ms ⁻¹ . The velocity of sound in air is 300 ~ms ⁻¹ . If the person can hear frequencies upto a maximum of 10,000 ~Hz , the maximum value of v upto which he can hear the whistle is
Options
- A30 ~ms ⁻¹
- B15 2 ~ms ⁻¹
- C15 / 2 ~ms ⁻¹
- D15 ~ms ⁻¹
Correct answer
D. 15 ~ms ⁻¹
Step-by-step solution
f_ a p p = f(300) 300-v v=15 ~m / s