JEE Main 20266 AprilEvening Shift
- Exam
- JEE Main
- Year
- 2026
- Date
- 6 April
- Shift
- Evening Shift
- Subject
- Chemistry
- Chapter
- Aldehydes and Ketones
JEE Main 2026 · 6 April · Evening Shift · Chemistry · Aldehydes and Ketones
' x ' is the product which is obtained by the hydrolysis of...
'' is the product which is obtained by the hydrolysis of prop-1-yne in the presence of mercuric sulphate under dilute acidic medium at K. '' is the product which is obtained by the reaction of ethane nitrile with methyl magnesium bromide in dry ether followed by hydrolysis. IUPAC name of product obtained from '' and '' in the presence of barium hydroxide followed by heating is :
Options
- A2-Methylpent-4-en-3-one
- B4-Methylpent-3-en-2-one
- C4-Methylpent-1-ene
- D2-Methylpent-3-one
Correct answer
B. 4-Methylpent-3-en-2-one
Step-by-step solution
Hydrolysis of prop-1-yne in the presence of and dilute yields acetone.
Thus, is acetone.
Reaction of ethane nitrile () with methyl magnesium bromide () followed by hydrolysis also yields acetone.
Thus, is acetone.
Reaction of and (both acetone) in the presence of followed by heating results in an aldol condensation.
Heating causes dehydration to form an unsaturated ketone.
Numbering the principal carbon chain to give the lowest locant to the ketone group, the IUPAC name of the product is 4-methylpent-3-en-2-one.
Answer: 4-Methylpent-3-en-2-one
Thus, is acetone.
Reaction of ethane nitrile () with methyl magnesium bromide () followed by hydrolysis also yields acetone.
Thus, is acetone.
Reaction of and (both acetone) in the presence of followed by heating results in an aldol condensation.
Heating causes dehydration to form an unsaturated ketone.
Numbering the principal carbon chain to give the lowest locant to the ketone group, the IUPAC name of the product is 4-methylpent-3-en-2-one.
Answer: 4-Methylpent-3-en-2-one