JEE Main 202623 JanuaryEvening Shift
- Exam
- JEE Main
- Year
- 2026
- Date
- 23 January
- Shift
- Evening Shift
- Subject
- Chemistry
- Chapter
- Aldehydes and Ketones
JEE Main 2026 · 23 January · Evening Shift · Chemistry · Aldehydes and Ketones
Which of the following statements are TRUE about Haloform...
Which of the following statements are TRUE about Haloform reaction?:
A. Sodium hypochlorite reacts with KI to give KOI.
B. KOI is a reducing agent.
C. -unsaturated methylketone \left(\mathrm{CH}_{3}-\mathrm{CH}=\mathrm{CH}-\stackrel{\mathrm{O}}{\mathrm{O}}-\mathrm{CH}_{3}\right) will give iodoform reaction.
D. Isopropyl alcohol will not give iodoform test.
E. Methanoic acid will give positive iodoform test.
Choose the correct answer from the options given below:
A. Sodium hypochlorite reacts with KI to give KOI.
B. KOI is a reducing agent.
C. -unsaturated methylketone \left(\mathrm{CH}_{3}-\mathrm{CH}=\mathrm{CH}-\stackrel{\mathrm{O}}{\mathrm{O}}-\mathrm{CH}_{3}\right) will give iodoform reaction.
D. Isopropyl alcohol will not give iodoform test.
E. Methanoic acid will give positive iodoform test.
Choose the correct answer from the options given below:
Options
- AA, C & E Only
- BB, D & E Only
- CA & C Only
- DA, B & C Only
Correct answer
C. A & C Only
Step-by-step solution
In the haloform reaction:
(A) Sodium hypochlorite reacts with KI in acidic medium to generate the active halogenating species, forming KOI (potassium iodite/hypoidite). TRUE.
(B) KOI serves as an oxidizing agent (not reducing) in the reaction, converting methyl ketones to carboxylic acids. FALSE.
(C) -unsaturated methylketones possess the essential methyl ketone group () required for haloform reaction, allowing iodination and subsequent cleavage. TRUE.
(D) Isopropyl alcohol lacks a methyl ketone group, so it cannot undergo the haloform reaction. TRUE.
(E) Formic acid has no methyl ketone functionality, preventing haloform test. FALSE.
Therefore, statements A and C are true.
(A) Sodium hypochlorite reacts with KI in acidic medium to generate the active halogenating species, forming KOI (potassium iodite/hypoidite). TRUE.
(B) KOI serves as an oxidizing agent (not reducing) in the reaction, converting methyl ketones to carboxylic acids. FALSE.
(C) -unsaturated methylketones possess the essential methyl ketone group () required for haloform reaction, allowing iodination and subsequent cleavage. TRUE.
(D) Isopropyl alcohol lacks a methyl ketone group, so it cannot undergo the haloform reaction. TRUE.
(E) Formic acid has no methyl ketone functionality, preventing haloform test. FALSE.
Therefore, statements A and C are true.