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JEE Main 202628 JanuaryEvening Shift
Exam
JEE Main
Year
2026
Date
28 January
Shift
Evening Shift
Subject
Chemistry
Chapter
Chemical Equilibrium

JEE Main 2026 · 28 January · Evening Shift · Chemistry · Chemical Equilibrium

Observe the following equilibrium in a 1 L flask. A(~g)...

Observe the following equilibrium in a 1 L flask.
A( g)⇌B( g)\mathrm{A}(\mathrm{~g}) \rightleftharpoons \mathrm{B}(\mathrm{~g})
At T(K)\mathrm{T}(\mathrm{K}), the equilibrium concentrations of A and B are 0.5 M and 0.375 M respectively. 0.1 moles of A is added into the flask and heated to T(K)\mathrm{T}(\mathrm{K}) to establish the equilibrium again. The new equilibrium concentrations (in M) of A and B are respectively

Options

  1. A0.53,0.40.53,0.4.
  2. B0.742,0.5570.742,0.557.
  3. C0.557,0.4180.557,0.418.
  4. D0.367,0.2750.367,0.275.

Correct answer

C. 0.557,0.4180.557,0.418.

Step-by-step solution

Initial equilibrium:
[A]=0.5 M, [B]=0.375 M; Kc=0.3750.5=0.75K_c=\frac{0.375}{0.5}=0.75
After adding 0.1 mol A: [A]=0.6 M, [B]=0.375 M; Q=0.625
Q < Kc, so equilibrium shifts right.
Let x be A that decomposes:
0.375+x0.6−x=0.75\frac{0.375+x}{0.6-x}=0.75
0.375+x=0.45-0.75x
1.75x=0.075; x≈0.0429
New [A]=0.6-0.0429=0.557 M; [B]=0.375+0.0429=0.418 M
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