Consider the following gaseous equilibrium in a closed container of volume ' V ' at T ( K ) . P ₂( ~g )+ Q ₂( ~g ) 2 PQ ( g ) 2 moles each of P ₂( ~g ), Q ₂( ~g ) and PQ ( g ) are present at equilibrium. Now one mole each of ' P ₂ ' and ' Q

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Consider the following gaseous equilibrium in a closed container of volume ' V ' at T ( K ) . P ₂( ~g )+ Q ₂( ~g ) 2 PQ ( g ) 2 moles each of P ₂( ~g ), Q ₂( ~g ) and PQ ( g ) are present at equilibrium. Now one mole each of ' P ₂ ' and ' Q ₂ ' are added to the equilibrium keeping the temperature at T ( K ) . The number of moles of P₂, Q₂ and P Q at the new equilibrium, respectively, are

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Correct answer: C. 2.67,2.67,2.67

Initial equilibrium: 2 moles each of P₂ , Q₂ , PQ with K = [PQ]^2 [P₂][Q₂] = 4 4 = 1 . After adding 1 mole each of P₂ and Q₂ : initial composition is (3, 3, 2) . Reaction quotient Q = 4 9 Let x moles of reactants combine: (2+2x)^2 (3-x)^2 = 1 2+2x = 3-x 3x = 1 → x = 1 3 Final moles: P₂ = 3 - 1 3 = 2.67 , Q₂ = 2.67 , PQ = 2 + 2 3 = 2.67

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