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JEE Main202621 January 2026Morning ShiftChemistryChemical EquilibriumActual

For the reaction, N ₂ O ₄ 2 NO ₂ , graph is plotted as shown below. Identify correct statements. A. Standard free energy change for the reaction is -5.40 ~kJ ~mol ⁻¹ . B. As G ^ in graph is positive, N ₂ O ₄ will not dissociate into NO ₂ at all. C. Reverse reaction will go to completion. D. When 1 mole of N ₂ O ₄ changes into equilibrium mixture, value of G ^ =-0.84 ~kJ ~mol ⁻¹ E. When 2 mole of NO ₂ changes into equ

Options

  1. AD and E only
  2. BA and D only
  3. CB and C only
  4. DC and E only

Correct answer

A. D and E only

Step-by-step solution

From the graph of G vs fraction of N₂O₄ dissociated: At x = 0 (pure N₂O₄ ): G = 0 At equilibrium ( x 0.4 ): G = -0.84 kJ/mol (minimum) At x = 1 (complete dissociation): G = 5.40 kJ/mol Statement A: G° = 5.40 kJ/mol (positive), not -5.40 kJ/mol. False. Statement B: Even with positive G° , equilibrium is established with partial dissociation. False. Statement C: Reverse reaction reaches equilibrium, not completion. False. Statement D: G = G_ eq - G_ N₂O₄ = -0.84 - 0 = -0.84 kJ/mol. True. Statement E: G = G_ eq - G_ N

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