37.8 ~g ~N ₂ O ₅ was taken in a 1 L reaction vessel and allowed to undergo the following reaction at 500 K 2 ~N ₂ O _ 5( ~g ) 2 ~N ₂ O _ 4( ~g ) + O _ 2( ~g ) The total pressure at equilibrium was found to be 18.65 bar. Then, Kp = ______ 10⁻² [nearest integer] Assume N ₂ O ₅ to behave ideally under these conditions. Given: R =0.082 bar L mol ⁻¹ ~K ⁻¹

Step-by-step solution

Initial pressure of N ₂ O ₅ aligned & = 37.8 108 0.082 500 1 =14.35 bar & 2 ~N ₂ O ₅ 2 ~N ₂ O ₄+ O ₂ aligned array lll t =0 & 14.35 t = eq & 14.35-2 P & 2 P array aligned & P _ Total at eqb =14.35+ P =18.65 & P =4.3 & P _ N ₂ O ₅ =5.75 bar & P _ N ₂ O ₄ =8.6 bar & P _ O ₂ =4.3 bar & k _ p = (8.6)^2 (4.3) (5.75)^2 =9.619= x 10⁻² & x =961.9 962 aligned