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JEE Main 202522 JanuaryMorning Shift
Exam
JEE Main
Year
2025
Date
22 January
Shift
Morning Shift
Subject
Chemistry
Chapter
Chemical Equilibrium

JEE Main 2025 · 22 January · Morning Shift · Chemistry · Chemical Equilibrium

A vessel at 1000 K contains CO_2 with a pressure of 0.5 atm . Some...

A vessel at 1000 K contains CO2\mathrm{CO}_2 with a pressure of 0.5 atm . Some of CO2\mathrm{CO}_2 is converted into CO on addition of graphite. If total pressure at equilibrium is 0.8 atm , then Kp is :

Options

  1. A1.8 atm
  2. B0.3 atm
  3. C3 atm
  4. D0.18 atm

Correct answer

A. 1.8 atm

Step-by-step solution

CO2(g)+C(s)⇌2CO(g)0.5−0.5−x2x\begin{array}{lc}\mathrm{CO}_2(\mathrm{ g})+\mathrm{C}(\mathrm{s}) \rightleftharpoons & 2 \mathrm{CO}(\mathrm{g}) \\ 0.5 & - \\ 0.5-\mathrm{x} & 2 \mathrm{x}\end{array} Ptotal =0.5+x=0.8x=0.3KP=(0.6)20.2=1.8\begin{aligned}\mathrm{P}_{\text{total }}=0.5+\mathrm{x}=0.8 \\ \mathrm{x}=0.3 \\ \mathrm{ K}_{\mathrm{P}}=\frac{(0.6)^2}{0.2}=1.8\end{aligned}$
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