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JEE Main 20248 AprilMorning Shift
Exam
JEE Main
Year
2024
Date
8 April
Shift
Morning Shift
Subject
Chemistry
Chapter
Chemical Equilibrium

JEE Main 2024 · 8 April · Morning Shift · Chemistry · Chemical Equilibrium

For the given hypothetical reactions, the equilibrium constants are...

For the given hypothetical reactions, the equilibrium constants are as follows : X⇌Y;K1=1.0Y⇌Z;K2=2.0Z⇌W;K3=4.0\begin{aligned} & \mathrm{X} \rightleftharpoons \mathrm{Y} ; \mathrm{K}_1=1.0 \\ & \mathrm{Y} \rightleftharpoons \mathrm{Z} ; \mathrm{K}_2=2.0 \\ & \mathrm{Z} \rightleftharpoons \mathrm{W} ; \mathrm{K}_3=4.0 \end{aligned})TheTheequilibrium constant for the reaction (\mathrm{X} \rightleftharpoons \mathrm{W}) is$

Options

  1. A6.0
  2. B12.0
  3. C7.0
  4. D8.0

Correct answer

D. 8.0

Step-by-step solution

X⇌Yk1=1Y⇌Zk2=2Z⇌ωk3=4X⇌ωk1⋅k2⋅k3k=1×2×4k=8\begin{array}{ll} \mathrm{X} \rightleftharpoons \mathrm{Y} & \mathrm{k}_1=1 \\ \mathrm{Y} \rightleftharpoons \mathrm{Z} & \mathrm{k}_2=2 \\ \mathrm{Z} \rightleftharpoons \omega & \mathrm{k}_3=4 \\ \mathrm{X} \rightleftharpoons \omega & \mathrm{k}_1 \cdot \mathrm{k}_2 \cdot \mathrm{k}_3 \\ & \mathrm{k}=1 \times 2 \times 4 \\ & \mathrm{k}=8 \end{array}
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