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JEE Main 20246 AprilMorning Shift
Exam
JEE Main
Year
2024
Date
6 April
Shift
Morning Shift
Subject
Chemistry
Chapter
Chemical Equilibrium

JEE Main 2024 · 6 April · Morning Shift · Chemistry · Chemical Equilibrium

At (-20^ ^ C ) and (1 ~atm ) pressure, a cylinder is filled with...

At (-20^{{}^{\circ}} C\mathrm{C}) and (1  atm\mathrm{~atm}) pressure, a cylinder is filled with equal number of (\mathrm{H}}_{2}, \mathrm{I}}_{2}) and (HI\mathrm{HI}) molecules for the reaction (\mathrm{H}}_{2}( \mathrm{~g})+\mathrm{I}}_{2}( g)⇌\mathrm{~g}) \rightleftharpoons2 HI(g)\mathrm{HI}(\mathrm{g})), the (Kp\mathrm{K}_{\mathrm{p}}) for the process is (x ×\times10^{-1}). (x=\mathrm{x}=) _____ [Given : (R=\mathrm{R}=0.082  L atm K−1 mol−1\mathrm{~L} \mathrm{~atm} \mathrm{~K}^{-1} \mathrm{~mol}^{-1})]

Options

  1. A0.01
  2. B10
  3. C2
  4. D1

Correct answer

B. 10

Step-by-step solution

Δng=0Kp=(nHI)2nH2nI2(PTnT)ΔngnHI=nH2=nI2 so KP=11=x×10−1x=10\begin{array}{ll}\Delta \mathrm{n}_{\mathrm{g}}=0 & \mathrm{ K}_{\mathrm{p}}=\frac{\left(\mathrm{n}_{\mathrm{HI}}\right)^2}{\mathrm{n}_{\mathrm{H}_2} \mathrm{n}_{\mathrm{I}_2}}\left(\frac{\mathrm{P}_{\mathrm{T}}}{\mathrm{n}_{\mathrm{T}}}\right)^{\Delta \mathrm{n}_{\mathrm{g}}} \\ \mathrm{n}_{\mathrm{HI}}=\mathrm{n}_{\mathrm{H}_2}=\mathrm{n}_{\mathrm{I}_2} & \text{ so } \mathrm{K}_{\mathrm{P}}=1 \\ 1=\mathrm{x} \times 10^{-1} & \mathrm{x}=10\end{array}
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