JEE Main202431 Jan 2024Evening ShiftChemistryChemical EquilibriumActual
A g ⇌ B g + C 2 g . The correct relationship between K P , α and equilibrium pressure P is
Options
- AK P = α 1 2 P 1 2 2 + α 1 2
- BK P = α 3 2 P 1 2 2 + α 1 2 1 − α
- CK P = α 1 2 P 3 2 2 + α 3 2
- DK P = α 1 2 P 1 2 2 + α 3 2
Correct answer
B. K P = α 3 2 P 1 2 2 + α 1 2 1 − α
Step-by-step solution
A g ⇌ B g + 1 2 C g at t = 0 1 0 0 at eq . 1 - α α α 2 Total moles at equilibrium: = 1 - α + α + α 2 = 1 + α 2 P B = α 1 + α 2 p P c = α 2 1 + α 2 p P A = 1 - α 1 + α 2 p K p = P B × P C 1 2 P A = α 1 + α 2 p α 2 1 + α 2 p 1 2 1 - α 1 + α 2 p K p = α 3 2 p 1 2 2 1 2 ( 1 - α ) 1 + α 2 1 2 K p = α 3 2 p 1 2 1 - α 2 + α 1 2