For a reaction at equilibrium A g ⇌ B g + 1 2 C g the relation between dissociation constant K , degree of dissociation α and equilibrium pressure p is given by :

Step-by-step solution

A g ⇌ B g + 1 2 C g at   t = 0 1 0 0 at   eq . 1 - α α α 2 total moles at eq. = 1 - α + α + α 2 = 1 + α 2 P B = α 1 + α 2 p               P c = α 2 1 + α 2 p             P A = 1 - α 1 + α 2 p K p = P B × P C 1 2 P A = α 1 + α 2 p α 2 1 + α 2 p 1 2 1 - α 1 + α 2 p K p = α 3 2 p 1 2 2 1 2 ( 1 - α ) 1 + α 2 1 2 k p = α 3