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JEE Main 20204 SeptemberEvening Shift

Exam: JEE Main
Year: 2020
Date: 4 September
Shift: Evening Shift
Subject: Chemistry
Chapter: Chemical Equilibrium

JEE Main 2020 · 4 September · Evening Shift · Chemistry · Chemical Equilibrium

If the equilibrium constant for A ⇌ B + C is K _ eq ^ ( 1 ) and...

If the equilibrium constant for

A ⇌ B + C

is

{K}_{eq}^{( 1 )}

and that of

B + C ⇌ P

is

{K}_{eq}^{( 2 )},

the equilibrium constant for

A ⇌ P

is :

Options

A ${K}_{eq}^{( 1 )} / {K}_{eq}^{( 2 )}$
B ${K}_{eq}^{( 2 )} - {K}_{eq}^{( 1 )}$
C ${K}_{eq}^{( 1 )} + {K}_{eq}^{( 2 )}$
D ${K}_{eq}^{( 1 )}{K}_{eq}^{( 2 )}$

Correct answer

D. ${K}_{eq}^{( 1 )}{K}_{eq}^{( 2 )}$

Step-by-step solution

On adding Reaction ${1}^{st}$ and Reaction ${2}^{nd}$ we get.

$A ⇌ P{K}_{eq} = {K}_{eq} ( 1 ) \cdot {K}_{eq} ( 2 )$

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