For the following reaction, equilibrium constant are given: S(s) +...

S$\left(s\right) + {O}_{2}\left(g\right) ⇌ S{O}_{2}\left(g\right)$; {k}_{1} = {10}^{52}&hellip;&hellip;(i)</p><p>2S\left(s\right) + 3{O}_{2}\left(g\right) ⇌ S{O}_{2}\left(g\right); {k}_{2} = {10}^{129}&hellip;&hellip;(ii)</p><p>2S{O}_{2}\left(g\right) + {O}_{2}\left(g\right) ⇌ 2S{O}_{3}\left(g\right); {k}_{eq} = ?$</p><p>${k}_{eq} = \dfrac{{\left[S{O}_{3}\right]}^{2}}{{\left[S{O}_{2}\right]}^{2}\left[{O}_{2}\right]}$</p><p>${k}_{1} = \dfrac{\left[S{O}_{2}\right]}{\left[{O}_{2}\right]} = {10}^{52}$</p><p>${k}_{2} = \dfrac{{\left[S{O}_{3}\right]}^{2}}{{\left[{O}_{2}\right]}^{3}} = {10}^{129}$</p><p>${k}_{eq} = \dfrac{{k}_{2}}{{\left({k}_{1}\right)}^{2}} = \dfrac{{10}^{129}}{{\left({10}^{52}\right)}^{2}} = {10}^{25}