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(1) N ₂( ~g )+3 H ₂( ~g ) 2 NH ₃( ~g ), K ₁ (2) N ₂( ~g )+ O ₂( ~g ) 2 NO ( g ), K ₂ (3) H ₂( ~g )+ 1 2 O ₂( ~g ) H ₂ O ( g ), K ₃ The equation for the equilibrium constant of the reaction 2 NH ₃( ~g )+ 5 2 O ₂( ~g ) 2 NO ( g )+3 H ₂ O ( g ) , (K₄ ) in terms of K ₁, ~K ₂ and K ₃ is :

Options

  1. AK ₁ K ₂ ~K ₃
  2. BK ₁ K ₃^2 ~K ₂
  3. CK ₁ ~K ₂ ~K ₃
  4. DK ₂ K ₃^3 ~K ₁

Correct answer

D. K ₂ K ₃^3 ~K ₁

Step-by-step solution

To calculate the value of K ₄ in the given equation we should apply : eqn. (2) + eqn. (3) 3- eqn. (1) hence K ₄= K ₂ ~K ₃^3 ~K ₁

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