JEE Main 201323 AprilOnline
- Exam
- JEE Main
- Year
- 2013
- Date
- 23 April
- Mode
- Online
- Subject
- Chemistry
- Chapter
- Chemical Equilibrium
JEE Main 2013 · 23 April · Online · Chemistry · Chemical Equilibrium
(1) N_2( g)+3 H_2( g) leftharpoons 2 NH_3( g), K_1 (2) N_2( g)+O_2(...
(1)
(2)
(3)
The equation for the equilibrium constant of the reaction
2 () \rightleftharpoons\left(K_4\right)terms of \mathrm{K}_1, \mathrm{ K}_2\mathrm{K}_3 is :
Options
- A
- B
- C
- D
Correct answer
D.
Step-by-step solution
To calculate the value of in the given equation we should apply :
eqn. (2) eqn. eqn. (1)
hence