The value of K_p for the equilibrium reaction N ₂ O ₄(g) 2 NO ₂(g) is 2 . The percentage dissociation of N ₂ O ₄(g) at a pressure of 0.5 ~atm is

Step-by-step solution

array llcc & N ₂ O ₄( ~g ) 2 NO ₂( ~g ) & Initial moles & 1 & 0 & Moles of equil. & (1- ) & 2 array ( = degree of dissociation ) Total number of moles at equil. aligned & =(1- )+2 & =(1+ ) p_ N₂ O ₄ & = (1- ) (1+ ) P p_ N O₂ & = 2 (1+ ) P K_P & = (p_ N_O )^2 p_ N₂ O₄ = ( 2 (1+ ) P )^2 ( 1- 1+ ) P = 4 ^2 P 1- ^2 aligned aligned & Given, K_P=2, P=0.5 ~atm & K_P= 4 ^2 P 1- ^2 & = 4 ^2 0.5 1- ^2 & =0.707 0.71 & Percentage dissociation & =0.71 100=71 aligned