JEE Main2011ChemistryChemical EquilibriumActual
A vessel at 1000 ~K contains CO ₂ with a pressure of 0.5 ~atm . Some of the CO ₂ is converted into CO on the addition of graphite. If the total pressure at equilibrium is 0.8 ~atm , the value of K is
Options
- A3 ~atm
- B0.3 ~atm
- C0.18 ~atm
- D1.8 ~atm
Correct answer
D. 1.8 ~atm
Step-by-step solution
Total pressure at equilibrium =0.8 ~atm ; Total no.of moles =p+x . Therefore p n ; 0.5 0.8 = p p + x x =0.3 K _ p = P _ CO ^2 P _ CO ₂ = 0.6 0.6 0.2 =1.8 ~atm