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When N 2 O 5 is heated at certain temperature, it dissociates as N 2 O 5 g ⇌ N 2 O 3 g + O 2 g ; K c = 2.5 . At the same time N 2 O 3 also decomposes as : N 2 O 3 g ⇌ N 2 O g + O 2 g . If initially 4.0 moles of N 2 O 5 are taken in 1.0 litre flask and allowed to dissociation, concentration of O 2 at equilibrium is 2.5 M. Equilibrium concentration of N 2 O 5 is :

Options

  1. A1.0 M
  2. B1.5 M
  3. C1.834 M
  4. D1.846 M

Correct answer

C. 1.834 M

Step-by-step solution

N 2 O 5 ⇌ N 2 O 3 + O 2 4 - x x - y x + y N 2 O 3 ⇌ N 2 O + O 2 x - y y y + x ∵ O 2 = x + y = 2.5 and 2.5 = x + y x - y 4 - x for 1 st reaction K c = 2.5 = x - 2.5 + x × 2.5 4 - x = 2 x - 2.5 4 - x 2.5 4 - x = 2 x - 2.5 6.5 = 3 x ∴ x = 2.166 N 2 O 5 = 4 - x = 4 - 2.166 = 1.834 M

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