Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
99 Percentile Qs Bank for JEE MainChemistryChemical Equilibrium

In the relation, K p = K c ( R T ) Δ n the value of Δ n is:

Options

  1. ANumber of moles of gaseous reactants - number of moles of gaseous products in a balanced equation
  2. BNumber of moles of gaseous products - number of moles of gaseous reactants in a balanced equation
  3. CNumber of moles of gaseous products × number of moles of gaseous reactants in a balanced equation
  4. DNumber of moles of gaseous reactants + number of moles of gaseous products in a balanced equation

Correct answer

B. Number of moles of gaseous products - number of moles of gaseous reactants in a balanced equation

Step-by-step solution

In the relation, K p = K c ( R T ) Δ n , the term ∆ n refers to the difference in the total number of moles of gaseous products and the total number of moles of gaseous reactants. Hence, it can have either positive value or negative value. It can be zero or also an integer or a fraction. Δ n g = n g ( p ) - n g ( r )

Practice Chemical Equilibrium on Quantrex Academy →

More from Chemical Equilibrium

Consider the following reactions in which all the reactants and products are present in gaseous state 2xy x₂ + y₂ K₁ = 2.5 10^5 xy + 1 2 z₂ xyz K₂ = 5 10⁻³ The value of K₃ for the 2026Solid carbon, CaO and CaCO₃ are mixed and allowed to attain equilibrium at T K. CaCO ₃(s) CaO (s) + CO ₂(g) K_ p₁ = 0.08 atm C (s) + CO ₂(g) 2 CO (g) K_ p₂ = 2 atm The partial pres 2026In a closed flask at 600 K, one mole of X₂ Y₄ (g) attains equilibrium as given below : X ₂ Y ₄(g) 2 XY ₂(g) At equilibrium, 75 % X₂ Y₄ (g) was dissociated and the total pressure is 2026One mole each of He and A(g) are taken in a 10 L closed flask and heated to 400 K to establish the following equilibrium. A(g) B(g) . K_c for this reaction at 400 K is 4.0 . The pa 2026The reaction A(g) B(g) + C(g) was initiated with the amount ' a ' of A(g) . At equilibrium it is found that the amount of A(g) remaining is (a - x) at a total pressure of p . The e 2026The values of pressure equilibrium constant recorded at different temperatures for the following equilibrium reaction have been given below A(g) B(g) + C(g) 1 T ( K ⁻¹) ₁₀ K_p 0.05 2026For the following reaction at 50° C and at 2 atm pressure, 2N₂O₅(g) 2N₂O₄(g)+O₂(g) N₂O₅ is 50 % dissociated. The magnitude of standard free energy change at this temperature is x . 2026At T(K) , the equilibrium constant of A₂(g) + B₂(g) C(g) is 2.7 10⁻⁵ . What is the equilibrium constant for 1 3 A₂(g) + 1 3 B₂(g) 1 3 C(g) at the same temperature? 2026 Full Chemical Equilibrium list All 99 Percentile Qs Bank for JEE Main PYQs