99 Percentile Qs Bank for JEE MainChemistryChemical Equilibrium
When N 2 O 5 is heated at certain temperature, it dissociates as N 2 O 5 g ⇌ N 2 O 3 g + O 2 g , K c = 2.5 at the same time N 2 O 3 also decomposes as N 2 O 3 g ⇌ N 2 O g + O 2 g In initially 4 mol of N 2 O 5 are taken in 1 L flask and allowed to dissociate, concentration of O 2 at equilibrium is 2.5 M, equilibrium concentration of N 2 O 3 will be
Options
- A1.2
- B2.15
- C1.5
- D1.8
Correct answer
D. 1.8
Step-by-step solution
Solution writing equilibrium concentrations of simultaneous equilibria (V=1 Litre) N 2 O 5 4 - x ⇌ N 2 O 3 g x - y + O 2 g x + y ; K c = 2.5 N 2 O 3 x - y ⇌ N 2 O y + O 2 x + y O 2 = x + y = 2.5 K c = 2.5 = N 2 O 3 O 2 N 2 O 5 = x - y x + y 4 - x as y = 2.5 - x ; Substituting ( x - 2.5 + x ) 2.5 4 - x = 2.5 2 x - 2.5 = 4 - x ∴ 3 x = 6.5 ∴ x = 2.17 y = 0.33 N 2 O 3 = x - y = 2.17 - 0.33 x - y = 1.84 = N 2 O 3 Choice 1.8