99 Percentile Qs Bank for JEE MainChemistryHydrocarbons
Sodium acetate was electrolysed by Kolbe's method to form two gases (A ) and (B ) at anode. (C ) and (D ) are formed, when (B ) is heated with regulated supply of ( O ₂ ) or air in the presence of ( ( CH ₃ COO )₂ Mn ). ( C ) reacts with ( NaOH ) to form a salt. (A ) and (D ) are respectively,
Options
- A( CO ₂, CH ₃ COOH )
- B( CO ₂, H ₂ O )
- C( C ₂ H ₆, H ₂ O )
- D( CO ₂, H ₂ O ₂ )
Correct answer
C. ( C ₂ H ₆, H ₂ O )
Step-by-step solution
Kolbe electrolysis of ( CH ₃ COO ⁻ Na ⁺ ). At anode, ( aligned & CH ₃^*+ CH ₃^* CH ₃ ( A ) - CH ₃ & 2 CH ₃- CH ₃+7 O ₂ ( CH ₃ COO ₂ Mn . 4 CO ₂+ (D) 6 H ₂ O aligned ) ( CO ₂+ O ₂ (C) CO + O ₃ ) ( CO + NaOH (Salt) HCOONa ) Hence, (A ) is ( C ₂ H ₆ ) and (D ) is ( H ₂ O ).