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JEE Main

Exam: JEE Main
Subject: Chemistry
Chapter: Redox Reactions

JEE Main · Chemistry · Redox Reactions

The equivalent weight of which of the following is maximum? (Given:...

The equivalent weight of which of the following is maximum? (Given: atomic weights

\mathrm{Na}=23, \mathrm{Mn}=55, \mathrm{Cr}=52, \mathrm{~K}=19, \mathrm{O}=16, \mathrm{C}=12)

Options

A $Na_2C_2O_4.2H_2O$
B $\mathrm{KMnO}_4 \mid \mathrm{H}^{+}$
C $\mathrm{KMnO}_4 \mid \mathrm{H_2O}$
D $\mathrm{K}_2 \mathrm{Cr}_2 \mathrm{O}_7 \mid \mathrm{H}^{+}$

Correct answer

A. $Na_2C_2O_4.2H_2O$

Step-by-step solution

Equivalent weight

=\frac{\text { Molar mass }}{\mathrm{N}-\text { factor }}=\frac{\text { Molar mass }}{\text { Number of } \mathrme^{-} \text {lost or gained }}

for,

\mathrm{Na}_2 \mathrm{C}_2 \mathrm{O}_4 ; \mathrm{E}=\frac{134+36}{2}=85

for,

\mathrm{KMnO}_4 / \mathrm{H}^{+} ; \mathrm{E}=\frac{158}{5}=31.6

for,

\mathrm{KMn}_4 / \mathrm{H}_2 \mathrm{O} ; \mathrm{E}=\frac{158}{3}=52.66

for,

\mathrm{K}_2 \mathrm{Cr}_2 \mathrm{O}_7 / \mathrm{H}^{+} ; \mathrm{E}=\frac{294}{6}=49

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