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99 Percentile Qs Bank for JEE MainChemistryRedox Reactions

The equivalent weight of which of the following is maximum? (Given: atomic weights Na =23, Mn =55, Cr =52, ~K =19, O =16, C =12)

Options

  1. ANa₂C₂O₄.2H₂O
  2. BKMnO ₄ H ⁺
  3. CKMnO ₄ H₂O
  4. DK ₂ Cr ₂ O ₇ H ⁺

Correct answer

A. Na₂C₂O₄.2H₂O

Step-by-step solution

Equivalent weight = Molar mass N - factor = Molar mass Number of e ⁻ lost or gained for, Na ₂ C ₂ O ₄ ; E = 134+36 2 =85 for, KMnO ₄ / H ⁺ ; E = 158 5 =31.6 for, KMn ₄ / H ₂ O ; E = 158 3 =52.66 for, K ₂ Cr ₂ O ₇ / H ⁺ ; E = 294 6 =49

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