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JEE Main
Exam
JEE Main
Subject
Chemistry
Chapter
Redox Reactions

JEE Main · Chemistry · Redox Reactions

1 litre solution of& KIO _ 3 ~of unknown molarity is given to...

1 litre solution of& KIO3{KIO}_{3}~of unknown molarity is given to titrate with~KIKI in strong acid medium. 50 mL solution of KIO3{KIO}_{3}~requires 10 mL of 0.1 M~KIKI for complete reduction to I2{I}_{2}. The molarity of KIO3{KIO}_{3}& solution is :

Options

  1. A4×10−3M4 × 1 {0}^{- 3} M
  2. B4×10−4M4 × 1 {0}^{- 4} M
  3. C4×10−5M4 × 1 {0}^{- 5} M
  4. D4×10−2M4 × 1 {0}^{- 2} M

Correct answer

A. 4×10−3M4 × 1 {0}^{- 3} M

Step-by-step solution

{10e+2I5+→(I0)22I−→(I0)2+2e\begin{cases}1 0 \text{e} & + & 2 I^{5 +} & \to & {\left(I^{0}\right)}_{2} & & \\ & & 2 I^{-} & \to & {\left(I^{0}\right)}_{2} & + & 2 \text{e}\end{cases}

Meq. of KIO3{KIO}_{3} = Meq. of I−I^{-}

50×M×5=10×0.1×15 0 \times \text{M} \times 5 = 1 0 \times \text{0.1} \times 1

∴M=1250=4×10−3∴ M = \dfrac{1}{2 5 0} = 4 \times 1 {0}^{- 3}
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