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Equivalent weights of KMnO ₄ and K ₂ Cr ₂ O ₇ in acidic medium are respectively. (Molecular weight of KMnO ₄=M_A and Molecular weight of K ₂ Cr ₂ O ₇=M_B ).

Options

  1. AM_A 3 M_B 6
  2. BM_A 6 M_B 5
  3. CM_A 3 M_B 5
  4. DM_A 5 M_B 6

Correct answer

D. M_A 5 M_B 6

Step-by-step solution

Given that, Molecular weight of KMnO ₄=M_A MnO ₄⁻+8 H ⁺+5 e ⁻ Mn ²⁺+4 H ₂ O Equivalent weight of KMnO ₄ = Molecular weight 5 = M_A 5 Similarly, molecular weight of K ₂ Cr ₂ O ₇=M_B K ₂ Cr ₂ O ₇+14 H ⁺+6 e⁻ 2 ~K ⁺+2 Cr ³⁺+7 H ₂ O Equivalent weight of K ₂ Cr ₂ O ₇ = Molecular weight 6 = M_B 6

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