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A solution of 10 mL M 1 0 FeSO 4 was titrated with KMnO 4 solution in acidic medium of KMnO 4 used will be

Options

  1. A5 mL of 0.1 M
  2. B10 mL of 0.1 M
  3. C10 mL of 0.5 M
  4. D10 mL of 0.02 M

Correct answer

D. 10 mL of 0.02 M

Step-by-step solution

2 KMnO 4 + 3 H 2 SO 4 → K 2 SO 4 + 2 MnSO 4 + 3 H 2 O + 5 O 2 FeSO 4 + H 2 SO 4 + O ⟶ Fe 2 SO 4 3 + H 2 O × 5 2 KMnO 4 + 8 H 2 SO 4 + 1 0 FeSO 4 ⟶ Products M 1 V 1 n 1 = M 2 V 2 n 2 KMnO 4 FeSO 4 M 1 V 1 = n 1 n 2 M 2 V 2 = 2 1 0 × 1 0 × 1 1 0 = 1 5 for, M 1 V 1 = 0.02 x 10 = 1/5.

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